फलन (f(x)=-\frac{3}{(x+1)2}+2) का परिसर क्या है?

What is the range of (f(x)=-\frac{3}{(x+1)2}+2)?

Explanation opens after your attempt
Correct Answer

A. (\(-\infty,2\))

Step 1

Concept

(-\frac{3}{(x+1)2}) is always negative and never becomes (0). So (f(x)) is always less than (2).

Step 2

Why this answer is correct

The correct answer is A. (\(-\infty,2\)). (-\frac{3}{(x+1)2}) is always negative and never becomes (0). So (f(x)) is always less than (2).

Step 3

Exam Tip

(-\frac{3}{(x+1)2}) हमेशा ऋणात्मक होता है और (0) नहीं बनता। इसलिए (f(x)) हमेशा (2) से कम है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=-\frac{3}{(x+1)2}+2) का परिसर क्या है? / What is the range of (f(x)=-\frac{3}{(x+1)2}+2)?

Correct Answer: A. (\(-\infty,2\)). Explanation: (-\frac{3}{(x+1)2}) हमेशा ऋणात्मक होता है और (0) नहीं बनता। इसलिए (f(x)) हमेशा (2) से कम है। / (-\frac{3}{(x+1)2}) is always negative and never becomes (0). So (f(x)) is always less than (2).

Which concept should I revise for this Mathematics MCQ?

(-\frac{3}{(x+1)2}) is always negative and never becomes (0). So (f(x)) is always less than (2).

What exam hint can help solve this Mathematics question?

(-\frac{3}{(x+1)2}) हमेशा ऋणात्मक होता है और (0) नहीं बनता। इसलिए (f(x)) हमेशा (2) से कम है।