फलन (f(x)=\frac{1}{x-2-4x+5}) का परिसर क्या है?
What is the range of (f(x)=\frac{1}{x-2-4x+5})?
Explanation opens after your attempt
A. ((0,1])
Concept
The denominator (x-2-4x+5=(x-2)2+1\ge 1). Hence (0<f(x)\le 1).
Why this answer is correct
The correct answer is A. ((0,1]). The denominator (x-2-4x+5=(x-2)2+1\ge 1). Hence (0<f(x)\le 1).
Exam Tip
हर (x-2-4x+5=(x-2)2+1\ge 1)। इसलिए (0<f(x)\le 1)।
Login to save your score, XP, coins and progress.
