फलन \(y=\frac{2x+1}{x-3}\) का क्षैतिज आसम्टोट क्या है?

What is the horizontal asymptote of \(y=\frac{2x+1}{x-3}\)?

Explanation opens after your attempt
Correct Answer

A. (y=2)

Step 1

Concept

The numerator and denominator have equal degree, so take the ratio of leading coefficients. Since \(\frac{2}{1}=2\), the asymptote is (y=2).

Step 2

Why this answer is correct

The correct answer is A. (y=2). The numerator and denominator have equal degree, so take the ratio of leading coefficients. Since \(\frac{2}{1}=2\), the asymptote is (y=2).

Step 3

Exam Tip

अंश और हर की डिग्री समान है इसलिए प्रमुख गुणांकों का अनुपात लें। \(\frac{2}{1}=2\) से आसम्टोट (y=2) है।

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Mathematics Answer, Explanation and Revision Hints

फलन \(y=\frac{2x+1}{x-3}\) का क्षैतिज आसम्टोट क्या है? / What is the horizontal asymptote of \(y=\frac{2x+1}{x-3}\)?

Correct Answer: A. (y=2). Explanation: अंश और हर की डिग्री समान है इसलिए प्रमुख गुणांकों का अनुपात लें। \(\frac{2}{1}=2\) से आसम्टोट (y=2) है। / The numerator and denominator have equal degree, so take the ratio of leading coefficients. Since \(\frac{2}{1}=2\), the asymptote is (y=2).

Which concept should I revise for this Mathematics MCQ?

The numerator and denominator have equal degree, so take the ratio of leading coefficients. Since \(\frac{2}{1}=2\), the asymptote is (y=2).

What exam hint can help solve this Mathematics question?

अंश और हर की डिग्री समान है इसलिए प्रमुख गुणांकों का अनुपात लें। \(\frac{2}{1}=2\) से आसम्टोट (y=2) है।