फलन (f(x)=\sqrt{x-4}+\sqrt{10-x}+\frac{1}{x-6}) का डोमेन क्या है?

What is the domain of (f(x)=\sqrt{x-4}+\sqrt{10-x}+\frac{1}{x-6})?

Explanation opens after your attempt
Correct Answer

A. \([4,10]\setminus{6}\)

Step 1

Concept

The two square roots give \(4\le x\le10\) and the denominator gives \(x\ne6\). In exams take the intersection of all conditions.

Step 2

Why this answer is correct

The correct answer is A. \([4,10]\setminus{6}\). The two square roots give \(4\le x\le10\) and the denominator gives \(x\ne6\). In exams take the intersection of all conditions.

Step 3

Exam Tip

दोनों वर्गमूलों से \(4\le x\le10\) और हर से \(x\ne6\) चाहिए। परीक्षा में सभी शर्तों का प्रतिच्छेद लें।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{x-4}+\sqrt{10-x}+\frac{1}{x-6}) का डोमेन क्या है? / What is the domain of (f(x)=\sqrt{x-4}+\sqrt{10-x}+\frac{1}{x-6})?

Correct Answer: A. \([4,10]\setminus{6}\). Explanation: दोनों वर्गमूलों से \(4\le x\le10\) और हर से \(x\ne6\) चाहिए। परीक्षा में सभी शर्तों का प्रतिच्छेद लें। / The two square roots give \(4\le x\le10\) and the denominator gives \(x\ne6\). In exams take the intersection of all conditions.

Which concept should I revise for this Mathematics MCQ?

The two square roots give \(4\le x\le10\) and the denominator gives \(x\ne6\). In exams take the intersection of all conditions.

What exam hint can help solve this Mathematics question?

दोनों वर्गमूलों से \(4\le x\le10\) और हर से \(x\ne6\) चाहिए। परीक्षा में सभी शर्तों का प्रतिच्छेद लें।