फलन (f(x)=\frac{x+2}{x-2-4}) का डोमेन क्या है?

What is the domain of (f(x)=\frac{x+2}{x-2-4})?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\setminus{-2,2}\)

Step 1

Concept

The original denominator is (x-2-4=(x-2)(x+2)), so \(x\ne -2,2\). In exams remove zeros of the original denominator before cancellation.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\setminus{-2,2}\). The original denominator is (x-2-4=(x-2)(x+2)), so \(x\ne -2,2\). In exams remove zeros of the original denominator before cancellation.

Step 3

Exam Tip

मूल हर (x-2-4=(x-2)(x+2)) है, इसलिए \(x\ne -2,2\)। परीक्षा में काटने से पहले मूल हर के शून्य हटाएं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{x+2}{x-2-4}) का डोमेन क्या है? / What is the domain of (f(x)=\frac{x+2}{x-2-4})?

Correct Answer: A. \(\mathbb{R}\setminus{-2,2}\). Explanation: मूल हर (x-2-4=(x-2)(x+2)) है, इसलिए \(x\ne -2,2\)। परीक्षा में काटने से पहले मूल हर के शून्य हटाएं। / The original denominator is (x-2-4=(x-2)(x+2)), so \(x\ne -2,2\). In exams remove zeros of the original denominator before cancellation.

Which concept should I revise for this Mathematics MCQ?

The original denominator is (x-2-4=(x-2)(x+2)), so \(x\ne -2,2\). In exams remove zeros of the original denominator before cancellation.

What exam hint can help solve this Mathematics question?

मूल हर (x-2-4=(x-2)(x+2)) है, इसलिए \(x\ne -2,2\)। परीक्षा में काटने से पहले मूल हर के शून्य हटाएं।