असमानता \( \frac{x-2}{3}\geq 4 \) का सही हल क्या है?
What is the correct solution of \( \frac{x-2}{3}\geq 4 \)?
Explanation opens after your attempt
Correct Answer
C. \(x\geq 14\)
Concept
Since (3) is positive, the sign does not change and \(x-2\geq 12\) gives \(x\geq 14\). With positive multiplication, the sign remains the same.
Why this answer is correct
The correct answer is C. \(x\geq 14\). Since (3) is positive, the sign does not change and \(x-2\geq 12\) gives \(x\geq 14\). With positive multiplication, the sign remains the same.
Exam Tip
(3) धनात्मक है इसलिए चिन्ह नहीं बदलता और \(x-2\geq 12\) से \(x\geq 14\) मिलता है। धनात्मक गुणन में चिन्ह वैसा ही रहता है।
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