असमानता \(\frac{2x-1}{3}\ge \frac{x+5}{2}\) का सही हल कौन सा है?
What is the correct solution of \(\frac{2x-1}{3}\ge \frac{x+5}{2}\)?
Explanation opens after your attempt
A. \(x\ge 17\)
Concept
Multiplying by positive (6) gives (2(2x-1)\ge 3(x+5)), hence \(x\ge 17\). A positive multiplier used to clear denominators does not change the sign.
Why this answer is correct
The correct answer is A. \(x\ge 17\). Multiplying by positive (6) gives (2(2x-1)\ge 3(x+5)), hence \(x\ge 17\). A positive multiplier used to clear denominators does not change the sign.
Exam Tip
धनात्मक (6) से गुणा करने पर (2(2x-1)\ge 3(x+5)), इसलिए \(x\ge 17\) है। हर हटाते समय धनात्मक गुणक चिन्ह नहीं बदलता।
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