( (1+x)5(1+x)7 ) में \(x^8\) का गुणांक कितना है?

What is the coefficient of \(x^8\) in ( (1+x)5(1+x)7 )?

Explanation opens after your attempt
Correct Answer

D. (495)

Step 1

Concept

The product is ( (1+x)^{12} ), so the coefficient is \( \binom{12}{8}=495 \). In binomial products, combine powers first.

Step 2

Why this answer is correct

The correct answer is D. (495). The product is ( (1+x)^{12} ), so the coefficient is \( \binom{12}{8}=495 \). In binomial products, combine powers first.

Step 3

Exam Tip

गुणनफल ( (1+x)^{12} ) है, इसलिए गुणांक \( \binom{12}{8}=495 \)। द्विपद गुणन में घातें जोड़कर सरल करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

( (1+x)5(1+x)7 ) में \(x^8\) का गुणांक कितना है? / What is the coefficient of \(x^8\) in ( (1+x)5(1+x)7 )?

Correct Answer: D. (495). Explanation: गुणनफल ( (1+x)^{12} ) है, इसलिए गुणांक \( \binom{12}{8}=495 \)। द्विपद गुणन में घातें जोड़कर सरल करें। / The product is ( (1+x)^{12} ), so the coefficient is \( \binom{12}{8}=495 \). In binomial products, combine powers first.

Which concept should I revise for this Mathematics MCQ?

The product is ( (1+x)^{12} ), so the coefficient is \( \binom{12}{8}=495 \). In binomial products, combine powers first.

What exam hint can help solve this Mathematics question?

गुणनफल ( (1+x)^{12} ) है, इसलिए गुणांक \( \binom{12}{8}=495 \)। द्विपद गुणन में घातें जोड़कर सरल करें।