द्विपद प्रसार में ( (1+x)^{12} ) का \( x^5 \) वाला गुणांक कितना है?
What is the coefficient of \( x^5 \) in the expansion of ( (1+x)^{12} )?
Explanation opens after your attempt
Correct Answer
D. (792)
Concept
The coefficient is \( \binom{12}{5} \), so the answer is (792). In exams, for ( (1+x)^n ), the coefficient of \(x^r\) is \( \binom{n}{r} \).
Why this answer is correct
The correct answer is D. (792). The coefficient is \( \binom{12}{5} \), so the answer is (792). In exams, for ( (1+x)^n ), the coefficient of \(x^r\) is \( \binom{n}{r} \).
Exam Tip
गुणांक \( \binom{12}{5} \) है, इसलिए उत्तर (792) है। परीक्षा में ( (1+x)^n ) में \(x^r\) का गुणांक सीधे \( \binom{n}{r} \) लें।
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