प्रथम चतुर्थांश में \(x+3y\le 9\) से बने त्रिभुज का क्षेत्रफल क्या है?
What is the area of the triangle formed by \(x+3y\le 9\) in the first quadrant?
Explanation opens after your attempt
Correct Answer
B. \(\frac{27}{2}\)
Concept
The intercepts are ((9,0)) and ((0,3)), so area is \(\frac{1}{2}\times 9\times 3=\frac{27}{2}\). For an axial triangle, use intercepts as base and height.
Why this answer is correct
The correct answer is B. \(\frac{27}{2}\). The intercepts are ((9,0)) and ((0,3)), so area is \(\frac{1}{2}\times 9\times 3=\frac{27}{2}\). For an axial triangle, use intercepts as base and height.
Exam Tip
अवरोध ((9,0)) और ((0,3)) हैं, इसलिए क्षेत्रफल \(\frac{1}{2}\times 9\times 3=\frac{27}{2}\)। अक्षीय त्रिभुज में अवरोधों को आधार और ऊंचाई लें।
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