पास्कल पहचान से \(\binom{6}{2}+\binom{6}{3}\) किसके बराबर है?

Using Pascal's identity, \(\binom{6}{2}+\binom{6}{3}\) is equal to which expression?

Explanation opens after your attempt
Correct Answer

C. \(\binom{7}{4}\)

Step 1

Concept

By Pascal's identity, \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the correct expression is \(\binom{7}{3}\).

Step 2

Why this answer is correct

The correct answer is C. \(\binom{7}{4}\). By Pascal's identity, \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the correct expression is \(\binom{7}{3}\).

Step 3

Exam Tip

पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{7}{3}\) नहीं, सही \(\binom{7}{3}\) है।

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Mathematics Answer, Explanation and Revision Hints

पास्कल पहचान से \(\binom{6}{2}+\binom{6}{3}\) किसके बराबर है? / Using Pascal's identity, \(\binom{6}{2}+\binom{6}{3}\) is equal to which expression?

Correct Answer: C. \(\binom{7}{4}\). Explanation: पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{7}{3}\) नहीं, सही \(\binom{7}{3}\) है। / By Pascal's identity, \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the correct expression is \(\binom{7}{3}\).

Which concept should I revise for this Mathematics MCQ?

By Pascal's identity, \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\). Hence the correct expression is \(\binom{7}{3}\).

What exam hint can help solve this Mathematics question?

पास्कल पहचान से \(\binom{n}{r}+\binom{n}{r+1}=\binom{n+1}{r+1}\) होता है। इसलिए उत्तर \(\binom{7}{3}\) नहीं, सही \(\binom{7}{3}\) है।