असमानता \( \frac{5-2x}{3}\geq x-4 \) का हल है:

The solution of \( \frac{5-2x}{3}\geq x-4 \) is:

Explanation opens after your attempt
Correct Answer

A. \(x\leq \frac{17}{5}\)

Step 1

Concept

Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(x\leq \frac{17}{5}\). Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).

Step 3

Exam Tip

(3) से गुणा करने पर \(5-2x\geq 3x-12\) मिलता है। इससे \(17\geq 5x\) अर्थात \(x\leq \frac{17}{5}\) है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \( \frac{5-2x}{3}\geq x-4 \) का हल है: / The solution of \( \frac{5-2x}{3}\geq x-4 \) is:

Correct Answer: A. \(x\leq \frac{17}{5}\). Explanation: (3) से गुणा करने पर \(5-2x\geq 3x-12\) मिलता है। इससे \(17\geq 5x\) अर्थात \(x\leq \frac{17}{5}\) है। / Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).

What exam hint can help solve this Mathematics question?

(3) से गुणा करने पर \(5-2x\geq 3x-12\) मिलता है। इससे \(17\geq 5x\) अर्थात \(x\leq \frac{17}{5}\) है।