असमानता \( \frac{5-2x}{3}\geq x-4 \) का हल है:
The solution of \( \frac{5-2x}{3}\geq x-4 \) is:
Explanation opens after your attempt
A. \(x\leq \frac{17}{5}\)
Concept
Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).
Why this answer is correct
The correct answer is A. \(x\leq \frac{17}{5}\). Multiplying by (3) gives \(5-2x\geq 3x-12\). This gives \(17\geq 5x\), so \(x\leq \frac{17}{5}\).
Exam Tip
(3) से गुणा करने पर \(5-2x\geq 3x-12\) मिलता है। इससे \(17\geq 5x\) अर्थात \(x\leq \frac{17}{5}\) है।
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