असमानता \( \frac{2-5x}{3}\geq 4x-7 \) का हल है:
The solution of \( \frac{2-5x}{3}\geq 4x-7 \) is:
Explanation opens after your attempt
Correct Answer
A. \(x\leq \frac{23}{17}\)
Concept
Multiplying by (3) gives \(2-5x\geq 12x-21\). Thus \(23\geq 17x\) and \(x\leq \frac{23}{17}\).
Why this answer is correct
The correct answer is A. \(x\leq \frac{23}{17}\). Multiplying by (3) gives \(2-5x\geq 12x-21\). Thus \(23\geq 17x\) and \(x\leq \frac{23}{17}\).
Exam Tip
(3) से गुणा करने पर \(2-5x\geq 12x-21\) मिलता है। इससे \(23\geq 17x\) और \(x\leq \frac{23}{17}\) है।
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