संबंध \(R=\{(x,y):x^2+y^2=1,\ x\in{-1,0,1},\ y\in{-1,0,1}\}\) को \(X=\{-1,0,1\}\) से \(Y=\{-1,0,1\}\) में माना गया है। यह फलन क्यों नहीं है?
The relation \(R=\{(x,y):x^2+y^2=1,\ x\in{-1,0,1},\ y\in{-1,0,1}\}\) is considered from \(X=\{-1,0,1\}\) to \(Y=\{-1,0,1\}\). Why is it not a function?
Explanation opens after your attempt
Correct Answer
A. क्योंकि (x=0) की दो छवियां हैंBecause (x=0) has two images
Concept
At (x=0), both (y=1) and (y=-1) are possible. Circle-like relations often break uniqueness in function tests.
Why this answer is correct
The correct answer is A. क्योंकि (x=0) की दो छवियां हैं / Because (x=0) has two images. At (x=0), both (y=1) and (y=-1) are possible. Circle-like relations often break uniqueness in function tests.
Exam Tip
(x=0) पर (y=1) और (y=-1) दोनों संभव हैं। वृत्त जैसे संबंध अक्सर फलन-परीक्षा में अद्वितीयता तोड़ते हैं।
Login to save your score, XP, coins and progress.