पास्कल संबंध \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में \(^{n-1}C_{r-1}\) किस स्थिति को दिखाता है?

In Pascal's relation \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) what does \(^{n-1}C_{r-1}\) represent?

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Correct Answer

C. विशेष वस्तु को चुनकर बाकी (r-1) चुननाChoosing the special object and then choosing remaining (r-1)

Step 1

Concept

If the special object is chosen the remaining (r-1) objects must be chosen from (n-1). In exams write the included case separately.

Step 2

Why this answer is correct

The correct answer is C. विशेष वस्तु को चुनकर बाकी (r-1) चुनना / Choosing the special object and then choosing remaining (r-1). If the special object is chosen the remaining (r-1) objects must be chosen from (n-1). In exams write the included case separately.

Step 3

Exam Tip

यदि विशेष वस्तु चुनी गई है तो बाकी (r-1) वस्तुएँ (n-1) में से चुननी होंगी। परीक्षा में included case को अलग लिखें।

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Mathematics Answer, Explanation and Revision Hints

पास्कल संबंध \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में \(^{n-1}C_{r-1}\) किस स्थिति को दिखाता है? / In Pascal's relation \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) what does \(^{n-1}C_{r-1}\) represent?

Correct Answer: C. विशेष वस्तु को चुनकर बाकी (r-1) चुनना / Choosing the special object and then choosing remaining (r-1). Explanation: यदि विशेष वस्तु चुनी गई है तो बाकी (r-1) वस्तुएँ (n-1) में से चुननी होंगी। परीक्षा में included case को अलग लिखें। / If the special object is chosen the remaining (r-1) objects must be chosen from (n-1). In exams write the included case separately.

Which concept should I revise for this Mathematics MCQ?

If the special object is chosen the remaining (r-1) objects must be chosen from (n-1). In exams write the included case separately.

What exam hint can help solve this Mathematics question?

यदि विशेष वस्तु चुनी गई है तो बाकी (r-1) वस्तुएँ (n-1) में से चुननी होंगी। परीक्षा में included case को अलग लिखें।