\(^{n}C_r=\frac{n}{r},^{n-1}C_{r-1}\) में \(\frac{n}{r}\) का विचार किससे जुड़ा है?

In \(^{n}C_r=\frac{n}{r},^{n-1}C_{r-1}\) what is the idea behind \(\frac{n}{r}\)?

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Correct Answer

A. एक चुनी हुई वस्तु को चिह्नित करके दो तरह से गिननाCounting in two ways by marking one chosen object

Step 1

Concept

A marked selection can start by choosing one of (n) objects and then choosing the remaining (r-1). In exams identify double counting identities.

Step 2

Why this answer is correct

The correct answer is A. एक चुनी हुई वस्तु को चिह्नित करके दो तरह से गिनना / Counting in two ways by marking one chosen object. A marked selection can start by choosing one of (n) objects and then choosing the remaining (r-1). In exams identify double counting identities.

Step 3

Exam Tip

Marked selection को (n) तरीके से शुरू करके बाकी (r-1) चुना जा सकता है। परीक्षा में double counting identities पहचानें।

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Mathematics Answer, Explanation and Revision Hints

\(^{n}C_r=\frac{n}{r},^{n-1}C_{r-1}\) में \(\frac{n}{r}\) का विचार किससे जुड़ा है? / In \(^{n}C_r=\frac{n}{r},^{n-1}C_{r-1}\) what is the idea behind \(\frac{n}{r}\)?

Correct Answer: A. एक चुनी हुई वस्तु को चिह्नित करके दो तरह से गिनना / Counting in two ways by marking one chosen object. Explanation: Marked selection को (n) तरीके से शुरू करके बाकी (r-1) चुना जा सकता है। परीक्षा में double counting identities पहचानें। / A marked selection can start by choosing one of (n) objects and then choosing the remaining (r-1). In exams identify double counting identities.

Which concept should I revise for this Mathematics MCQ?

A marked selection can start by choosing one of (n) objects and then choosing the remaining (r-1). In exams identify double counting identities.

What exam hint can help solve this Mathematics question?

Marked selection को (n) तरीके से शुरू करके बाकी (r-1) चुना जा सकता है। परीक्षा में double counting identities पहचानें।