(4) फलों में से कम से कम (2) फल चुनने के कितने तरीके हैं?

In how many ways can at least (2) fruits be selected from (4) fruits?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

The ways are \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\). Add all possible values in at least questions.

Step 2

Why this answer is correct

The correct answer is C. (11). The ways are \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\). Add all possible values in at least questions.

Step 3

Exam Tip

तरीके \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\) हैं। कम से कम में सभी मान जोड़ें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

(4) फलों में से कम से कम (2) फल चुनने के कितने तरीके हैं? / In how many ways can at least (2) fruits be selected from (4) fruits?

Correct Answer: C. (11). Explanation: तरीके \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\) हैं। कम से कम में सभी मान जोड़ें। / The ways are \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\). Add all possible values in at least questions.

Which concept should I revise for this Mathematics MCQ?

The ways are \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\). Add all possible values in at least questions.

What exam hint can help solve this Mathematics question?

तरीके \(\binom{4}{2}+\binom{4}{3}+\binom{4}{4}=6+4+1=11\) हैं। कम से कम में सभी मान जोड़ें।