(7) डॉक्टरों और (4) नर्सों में से (2) डॉक्टर और (1) नर्स की टीम कितने तरीकों से बनेगी?

In how many ways can a team of (2) doctors and (1) nurse be formed from (7) doctors and (4) nurses?

Explanation opens after your attempt
Correct Answer

C. (84)

Step 1

Concept

The ways are \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\). Count each condition separately.

Step 2

Why this answer is correct

The correct answer is C. (84). The ways are \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\). Count each condition separately.

Step 3

Exam Tip

तरीके \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\) हैं। शर्तों को अलग-अलग गिनें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

(7) डॉक्टरों और (4) नर्सों में से (2) डॉक्टर और (1) नर्स की टीम कितने तरीकों से बनेगी? / In how many ways can a team of (2) doctors and (1) nurse be formed from (7) doctors and (4) nurses?

Correct Answer: C. (84). Explanation: तरीके \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\) हैं। शर्तों को अलग-अलग गिनें। / The ways are \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\). Count each condition separately.

Which concept should I revise for this Mathematics MCQ?

The ways are \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\). Count each condition separately.

What exam hint can help solve this Mathematics question?

तरीके \(\binom{7}{2}\binom{4}{1}=21\cdot4=84\) हैं। शर्तों को अलग-अलग गिनें।