(5) अलग-अलग लाल और (4) अलग-अलग नीली गेंदों को ऐसे पंक्ति में रखें कि कोई दो नीली गेंदें साथ न हों। तरीकों की संख्या क्या है?
In how many ways can (5) distinct red balls and (4) distinct blue balls be arranged in a row so that no two blue balls are together?
Explanation opens after your attempt
Correct Answer
B. (86400)
Concept
Arrange the red balls first in (5!) ways, then place (4) blue balls in (6) gaps in \(^{6}P_4\) ways. The total is \(5!\cdot^{6}P_4=86400\).
Why this answer is correct
The correct answer is B. (86400). Arrange the red balls first in (5!) ways, then place (4) blue balls in (6) gaps in \(^{6}P_4\) ways. The total is \(5!\cdot^{6}P_4=86400\).
Exam Tip
पहले लाल गेंदें (5!) तरीकों से रखें, फिर (6) gaps में (4) नीली गेंदें \(^{6}P_4\) तरीकों से रखें। कुल \(5!\cdot^{6}P_4=86400\) है।
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