Class 11 Mathematics Permutations and Combinations Combinations Expert Level 62

(30) लोगों की सभा में (435) हाथ मिलाए गए। यदि हर जोड़ा एक बार हाथ मिलाता है, तो कितने लोग अनुपस्थित थे जब कुल आमंत्रित (35) थे?

In a gathering, (435) handshakes occurred. If every pair shook hands once and (35) people were invited, how many were absent?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

From \(^{n}C_{2}=435\), (n=30) people were present. Therefore absent people are (35-30=5).

Step 2

Why this answer is correct

The correct answer is C. (5). From \(^{n}C_{2}=435\), (n=30) people were present. Therefore absent people are (35-30=5).

Step 3

Exam Tip

\(^{n}C_{2}=435\) से (n=30) उपस्थित हैं। अतः अनुपस्थित (35-30=5)।

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(30) लोगों की सभा में (435) हाथ मिलाए गए। यदि हर जोड़ा एक बार हाथ मिलाता है, तो कितने लोग अनुपस्थित थे जब कुल आमंत्रित (35) थे? / In a gathering, (435) handshakes occurred. If every pair shook hands once and (35) people were invited, how many were absent?

Correct Answer: C. (5). Explanation: \(^{n}C_{2}=435\) से (n=30) उपस्थित हैं। अतः अनुपस्थित (35-30=5)। / From \(^{n}C_{2}=435\), (n=30) people were present. Therefore absent people are (35-30=5).

Which concept should I revise for this Mathematics MCQ?

From \(^{n}C_{2}=435\), (n=30) people were present. Therefore absent people are (35-30=5).

What exam hint can help solve this Mathematics question?

\(^{n}C_{2}=435\) से (n=30) उपस्थित हैं। अतः अनुपस्थित (35-30=5)।