यदि \(Z={x:x\in \mathbb{Z}, x^2\leq 4}\) है, तो (Z) में कितने अवयव हैं?
If \(Z={x:x\in \mathbb{Z}, x^2\leq 4}\), how many elements does (Z) have?
Explanation opens after your attempt
C. (5)
Concept
\(x^2\leq 4\) gives \(-2\leq x\leq 2\).
Why this answer is correct
The integers are (-2,-1,0,1,2), so there are (5).
Exam Tip
When the sign is \(\leq\), count the boundary values too. चरण 1: \(x^2\leq 4\) से \(-2\leq x\leq 2\) मिलता है। चरण 2: पूर्णांक (-2,-1,0,1,2) हैं, कुल (5)। चरण 3: \(\leq\) होने पर किनारे के मान भी गिनें।
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