यदि \(x\in\mathbb{Z}\) और \(-2\le\frac{3x-1}{2}<5\), तो हल समुच्चय कौन सा है?

If \(x\in\mathbb{Z}\) and \(-2\le\frac{3x-1}{2}<5\), what is the solution set?

Explanation opens after your attempt
Correct Answer

A. ({-1,0,1,2,3})

Step 1

Concept

The solution is \(-1\le x<\frac{11}{3}\), so the integers are ({-1,0,1,2,3}). In exams write the final answer according to the domain.

Step 2

Why this answer is correct

The correct answer is A. ({-1,0,1,2,3}). The solution is \(-1\le x<\frac{11}{3}\), so the integers are ({-1,0,1,2,3}). In exams write the final answer according to the domain.

Step 3

Exam Tip

हल \(-1\le x<\frac{11}{3}\) है, इसलिए पूर्णांक ({-1,0,1,2,3}) मिलते हैं। परीक्षा में अंतिम उत्तर डोमेन के अनुसार लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in\mathbb{Z}\) और \(-2\le\frac{3x-1}{2}<5\), तो हल समुच्चय कौन सा है? / If \(x\in\mathbb{Z}\) and \(-2\le\frac{3x-1}{2}<5\), what is the solution set?

Correct Answer: A. ({-1,0,1,2,3}). Explanation: हल \(-1\le x<\frac{11}{3}\) है, इसलिए पूर्णांक ({-1,0,1,2,3}) मिलते हैं। परीक्षा में अंतिम उत्तर डोमेन के अनुसार लिखें। / The solution is \(-1\le x<\frac{11}{3}\), so the integers are ({-1,0,1,2,3}). In exams write the final answer according to the domain.

Which concept should I revise for this Mathematics MCQ?

The solution is \(-1\le x<\frac{11}{3}\), so the integers are ({-1,0,1,2,3}). In exams write the final answer according to the domain.

What exam hint can help solve this Mathematics question?

हल \(-1\le x<\frac{11}{3}\) है, इसलिए पूर्णांक ({-1,0,1,2,3}) मिलते हैं। परीक्षा में अंतिम उत्तर डोमेन के अनुसार लिखें।