यदि \(x\in(1,4)\) है, तो \(\frac{x-1}{3}\) किस अंतराल में होगा?

If \(x\in(1,4)\), in which interval will \(\frac{x-1}{3}\) lie?

Explanation opens after your attempt
Correct Answer

A. ((0,1))

Step 1

Concept

From (1<x<4), we get (0<x-1<3), then dividing by positive (3) gives \(0<\frac{x-1}{3}<1\). Division by a positive number does not change the sign.

Step 2

Why this answer is correct

The correct answer is A. ((0,1)). From (1<x<4), we get (0<x-1<3), then dividing by positive (3) gives \(0<\frac{x-1}{3}<1\). Division by a positive number does not change the sign.

Step 3

Exam Tip

(1<x<4) से (0<x-1<3), फिर धनात्मक (3) से भाग देने पर \(0<\frac{x-1}{3}<1\) मिलता है। धनात्मक भाग में चिन्ह नहीं बदलता।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in(1,4)\) है, तो \(\frac{x-1}{3}\) किस अंतराल में होगा? / If \(x\in(1,4)\), in which interval will \(\frac{x-1}{3}\) lie?

Correct Answer: A. ((0,1)). Explanation: (1<x<4) से (0<x-1<3), फिर धनात्मक (3) से भाग देने पर \(0<\frac{x-1}{3}<1\) मिलता है। धनात्मक भाग में चिन्ह नहीं बदलता। / From (1<x<4), we get (0<x-1<3), then dividing by positive (3) gives \(0<\frac{x-1}{3}<1\). Division by a positive number does not change the sign.

Which concept should I revise for this Mathematics MCQ?

From (1<x<4), we get (0<x-1<3), then dividing by positive (3) gives \(0<\frac{x-1}{3}<1\). Division by a positive number does not change the sign.

What exam hint can help solve this Mathematics question?

(1<x<4) से (0<x-1<3), फिर धनात्मक (3) से भाग देने पर \(0<\frac{x-1}{3}<1\) मिलता है। धनात्मक भाग में चिन्ह नहीं बदलता।