\(यदि (U={x:x\) एक अंक है\(}) और (A={x:x\) सम अंक है\(}), तो (A^c) में कितने तत्व हैं\)?

\(If (U={x:x\) is a digit\(}) and (A={x:x\) is an even digit\(}), how many elements are in (A^c)\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

The digit set is \(U=\{0,1,2,3,4,5,6,7,8,9\}\). There are (5) even digits, so there are (5) odd digits.

Step 2

Why this answer is correct

The correct answer is A. (5). The digit set is \(U=\{0,1,2,3,4,5,6,7,8,9\}\). There are (5) even digits, so there are (5) odd digits.

Step 3

Exam Tip

अंकों का \(U=\{0,1,2,3,4,5,6,7,8,9\}\) है। सम अंक (5) हैं, इसलिए विषम अंक भी (5) हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(यदि (U={x:x\) एक अंक है\(}) और (A={x:x\) सम अंक है}), तो \(A^c\) में कितने तत्व हैं? \(/ If (U={x:x\) is a digit\(}) and (A={x:x\) is an even digit\(}), how many elements are in (A^c)\)?

Correct Answer: A. (5). Explanation: अंकों का \(U=\{0,1,2,3,4,5,6,7,8,9\}\) है। सम अंक (5) हैं, इसलिए विषम अंक भी (5) हैं। / The digit set is \(U=\{0,1,2,3,4,5,6,7,8,9\}\). There are (5) even digits, so there are (5) odd digits.

Which concept should I revise for this Mathematics MCQ?

The digit set is \(U=\{0,1,2,3,4,5,6,7,8,9\}\). There are (5) even digits, so there are (5) odd digits.

What exam hint can help solve this Mathematics question?

अंकों का \(U=\{0,1,2,3,4,5,6,7,8,9\}\) है। सम अंक (5) हैं, इसलिए विषम अंक भी (5) हैं।