यदि \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) और \(A={x:x^2=9}\) है, तो \(A^c\) में कितने तत्व होंगे?
If \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) and \(A={x:x^2=9}\), how many elements are in \(A^c\)?
Explanation opens after your attempt
A. (9)
Concept
There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).
Why this answer is correct
The correct answer is A. (9). There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).
Exam Tip
(U) में (11) पूर्णांक हैं और \(A=\{-3,3\}\) है। इसलिए (n\(A^c\)=11-2=9) होगा।
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