यदि \(U={x:x \in \mathbb{Z},-4\le x\le 6}\) और \(A=\{x:x \in U,(x-1)(x+2)\ge 0\}\), तो (A') क्या है?
If \(U={x:x \in \mathbb{Z},-4\le x\le 6}\) and \(A=\{x:x \in U,(x-1)(x+2)\ge 0\}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ({-1,0})
Concept
The solution of ((x-1)(x+2)\ge 0) is \(x\le -2\) or \(x\ge 1\). Thus the middle integers (-1,0) are in the complement.
Why this answer is correct
The correct answer is A. ({-1,0}). The solution of ((x-1)(x+2)\ge 0) is \(x\le -2\) or \(x\ge 1\). Thus the middle integers (-1,0) are in the complement.
Exam Tip
((x-1)(x+2)\ge 0) का हल \(x\le -2\) या \(x\ge 1\) है। इसलिए बीच के पूर्णांक (-1,0) पूरक में आते हैं।
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