यदि \(U={x:x\in\mathbb{Z},-3\le x\le 8}\), \(A={x:x\in U,x+1\ge 4}\) और \(B={x:x\in U,x<6}\), तो \(A'\cup B'\) क्या है?
If \(U={x:x\in\mathbb{Z},-3\le x\le 8}\), \(A={x:x\in U,x+1\ge 4}\), and \(B={x:x\in U,x<6}\), what is \(A'\cup B'\)?
Explanation opens after your attempt
Correct Answer
A. ({-3,-2,-1,0,1,2,6,7,8})
Concept
\(A=\{3,4,5,6,7,8\}\) and \(B=\{-3,-2,-1,0,1,2,3,4,5\}\). Thus \(A'\cup B'\) contains all elements except (3,4,5).
Why this answer is correct
The correct answer is A. ({-3,-2,-1,0,1,2,6,7,8}). \(A=\{3,4,5,6,7,8\}\) and \(B=\{-3,-2,-1,0,1,2,3,4,5\}\). Thus \(A'\cup B'\) contains all elements except (3,4,5).
Exam Tip
\(A=\{3,4,5,6,7,8\}\) और \(B=\{-3,-2,-1,0,1,2,3,4,5\}\) हैं। इसलिए \(A'\cup B'\) में (3,4,5) को छोड़कर सभी सदस्य हैं।
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