यदि \(U={x:x \in \mathbb{Z},1\le x\le 30}\) और \(A={x:x \in U,x \equiv 1 \pmod{4}}\), तो (n(A')) क्या है?

If \(U={x:x \in \mathbb{Z},1\le x\le 30}\) and \(A={x:x \in U,x \equiv 1 \pmod{4}}\), what is (n(A'))?

Explanation opens after your attempt
Correct Answer

A. (22)

Step 1

Concept

The elements (1,5,9,13,17,21,25,29), so (8) elements, are in (A). Hence (n(A')=30-8=22).

Step 2

Why this answer is correct

The correct answer is A. (22). The elements (1,5,9,13,17,21,25,29), so (8) elements, are in (A). Hence (n(A')=30-8=22).

Step 3

Exam Tip

(1,5,9,13,17,21,25,29) यानी (8) सदस्य (A) में हैं। इसलिए (n(A')=30-8=22) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x \in \mathbb{Z},1\le x\le 30}\) और \(A={x:x \in U,x \equiv 1 \pmod{4}}\), तो (n(A')) क्या है? / If \(U={x:x \in \mathbb{Z},1\le x\le 30}\) and \(A={x:x \in U,x \equiv 1 \pmod{4}}\), what is (n(A'))?

Correct Answer: A. (22). Explanation: (1,5,9,13,17,21,25,29) यानी (8) सदस्य (A) में हैं। इसलिए (n(A')=30-8=22) है। / The elements (1,5,9,13,17,21,25,29), so (8) elements, are in (A). Hence (n(A')=30-8=22).

Which concept should I revise for this Mathematics MCQ?

The elements (1,5,9,13,17,21,25,29), so (8) elements, are in (A). Hence (n(A')=30-8=22).

What exam hint can help solve this Mathematics question?

(1,5,9,13,17,21,25,29) यानी (8) सदस्य (A) में हैं। इसलिए (n(A')=30-8=22) है।