यदि \(U={x:x \in \mathbb{Z},0\le x\le 20}\) और \(A={x:x \in U,x^2-9x+20=0}\), तो (A') में (5) से छोटे सदस्यों की संख्या कितनी है?

If \(U={x:x \in \mathbb{Z},0\le x\le 20}\) and \(A={x:x \in U,x^2-9x+20=0}\), how many elements of (A') are less than (5)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

The equation gives \(A=\{4,5\}\). Elements less than (5) are (0,1,2,3,4), and (4) is removed, so (4) elements remain.

Step 2

Why this answer is correct

The correct answer is A. (5). The equation gives \(A=\{4,5\}\). Elements less than (5) are (0,1,2,3,4), and (4) is removed, so (4) elements remain.

Step 3

Exam Tip

समीकरण से \(A=\{4,5\}\) है। (5) से छोटे सदस्य (0,1,2,3,4) हैं, इनमें (4) हटेगा, इसलिए (4) नहीं बल्कि (4) सदस्य बचते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x \in \mathbb{Z},0\le x\le 20}\) और \(A={x:x \in U,x^2-9x+20=0}\), तो (A') में (5) से छोटे सदस्यों की संख्या कितनी है? / If \(U={x:x \in \mathbb{Z},0\le x\le 20}\) and \(A={x:x \in U,x^2-9x+20=0}\), how many elements of (A') are less than (5)?

Correct Answer: A. (5). Explanation: समीकरण से \(A=\{4,5\}\) है। (5) से छोटे सदस्य (0,1,2,3,4) हैं, इनमें (4) हटेगा, इसलिए (4) नहीं बल्कि (4) सदस्य बचते हैं। / The equation gives \(A=\{4,5\}\). Elements less than (5) are (0,1,2,3,4), and (4) is removed, so (4) elements remain.

Which concept should I revise for this Mathematics MCQ?

The equation gives \(A=\{4,5\}\). Elements less than (5) are (0,1,2,3,4), and (4) is removed, so (4) elements remain.

What exam hint can help solve this Mathematics question?

समीकरण से \(A=\{4,5\}\) है। (5) से छोटे सदस्य (0,1,2,3,4) हैं, इनमें (4) हटेगा, इसलिए (4) नहीं बल्कि (4) सदस्य बचते हैं।