यदि \(U={x:x\in \mathbb{N}, x\leq 18}\) और \(A={x:x\) (4) का गुणज है(}), तो (A') में कितने तत्व होंगे?
If \(U={x:x\in \mathbb{N}, x\leq 18}\) and \(A={x:x\) is a multiple of (4)(}), how many elements are in (A')?
Explanation opens after your attempt
C. (14)
Concept
\(A=\{4,8,12,16\}\), so (n(A)=4). Since (U) has (18) elements, (n(A')=18-4=14).
Why this answer is correct
The correct answer is C. (14). \(A=\{4,8,12,16\}\), so (n(A)=4). Since (U) has (18) elements, (n(A')=18-4=14).
Exam Tip
\(A=\{4,8,12,16\}\) है इसलिए (n(A)=4)। (U) में (18) तत्व हैं अतः (n(A')=18-4=14)।
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