यदि \(U={x:x\in\mathbb{N},x\le 90}\), \(A={x:x\in U,10\mid x}\), \(B={x:x\in U,18\mid x}\), तो (n\(A'\cap B'\)) क्या है?
If \(U={x:x\in\mathbb{N},x\le 90}\), \(A={x:x\in U,10\mid x}\), and \(B={x:x\in U,18\mid x}\), what is (n\(A'\cap B'\))?
Explanation opens after your attempt
Correct Answer
A. (77)
Concept
(A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=9+5-1=13), the complement is (90-13=77).
Why this answer is correct
The correct answer is A. (77). (A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=9+5-1=13), the complement is (90-13=77).
Exam Tip
(A'\cap B'=\(A\cup B\)') है। (n\(A\cup B\)=9+5-1=13), इसलिए पूरक (90-13=77) है।
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