\(यदि (U={x:x\in \mathbb{N},x\le 40}), (A={x:x\) 4 से विभाज्य है\(}) और (B={x:x\) 6 से विभाज्य है\(}), तो (|(A\cap B)'|) कितना है\)?
\(If (U={x:x\in \mathbb{N},x\le 40}), (A={x:x\) is divisible by \(4}) and (B={x:x\) is divisible by \(6}), what is (|(A\cap B)'|)\)?
Explanation opens after your attempt
Correct Answer
B. (37)
Concept
\(A\cap B\) contains multiples of (12), namely (12,24,36), so it has (3) elements. Hence the complement has (40-3=37) elements.
Why this answer is correct
The correct answer is B. (37). \(A\cap B\) contains multiples of (12), namely (12,24,36), so it has (3) elements. Hence the complement has (40-3=37) elements.
Exam Tip
\(A\cap B\) में (12) के गुणज (12,24,36) हैं, इसलिए (3) अवयव हैं। अतः पूरक में (40-3=37) अवयव होंगे।
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