यदि \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\) और \(B={x:x\in U,27\mid x}\), तो \(B'\cap A\) में कितने सदस्य हैं?

If \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,27\mid x}\), how many elements are in \(B'\cap A\)?

Explanation opens after your attempt
Correct Answer

A. (24)

Step 1

Concept

(A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.

Step 2

Why this answer is correct

The correct answer is A. (24). (A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.

Step 3

Exam Tip

(A) में (3) के (27) गुणज हैं और (B) में (27) के (3) गुणज हैं। इसलिए \(B'\cap A\) में (27-3=24) सदस्य हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\) और \(B={x:x\in U,27\mid x}\), तो \(B'\cap A\) में कितने सदस्य हैं? / If \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,27\mid x}\), how many elements are in \(B'\cap A\)?

Correct Answer: A. (24). Explanation: (A) में (3) के (27) गुणज हैं और (B) में (27) के (3) गुणज हैं। इसलिए \(B'\cap A\) में (27-3=24) सदस्य हैं। / (A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.

Which concept should I revise for this Mathematics MCQ?

(A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.

What exam hint can help solve this Mathematics question?

(A) में (3) के (27) गुणज हैं और (B) में (27) के (3) गुणज हैं। इसलिए \(B'\cap A\) में (27-3=24) सदस्य हैं।