\(यदि (U={1,2,\ldots,70}), (A={x:x\) 5 से विभाज्य है\(}) और (B={x:x\) 7 से विभाज्य है\(}), तो (|A'\cap B|) कितना है\)?
\(If (U={1,2,\ldots,70}), (A={x:x\) is divisible by \(5}) and (B={x:x\) is divisible by \(7}), what is (|A'\cap B|)\)?
Explanation opens after your attempt
Correct Answer
C. (8)
Concept
(B) has (10) elements, and \(A\cap B\) has (2) multiples of (35). Therefore \(A'\cap B\) has (10-2=8) elements.
Why this answer is correct
The correct answer is C. (8). (B) has (10) elements, and \(A\cap B\) has (2) multiples of (35). Therefore \(A'\cap B\) has (10-2=8) elements.
Exam Tip
(B) में (10) अवयव हैं और \(A\cap B\) में (35) के (2) गुणज हैं। इसलिए \(A'\cap B\) में (10-2=8) अवयव हैं।
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