\(यदि (U={1,2,\ldots,36}), (A={x:x\) 2 से विभाज्य है\(}) और (B={x:x\) 3 से विभाज्य है\(}), तो (|(A'\cap B')|) कितना है\)?

\(If (U={1,2,\ldots,36}), (A={x:x\) is divisible by \(2}) and (B={x:x\) is divisible by \(3}), what is (|(A'\cap B')|)\)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

(A'\cap B'=\(A\cup B\)'). Since \(|A\cup B|=18+12-6=24\), the complement has (36-24=12) elements.

Step 2

Why this answer is correct

The correct answer is C. (12). (A'\cap B'=\(A\cup B\)'). Since \(|A\cup B|=18+12-6=24\), the complement has (36-24=12) elements.

Step 3

Exam Tip

(A'\cap B'=\(A\cup B\)') होता है। \(|A\cup B|=18+12-6=24\), इसलिए पूरक में (36-24=12) अवयव हैं।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,\ldots,36}), (A={x:x\) 2 से विभाज्य है\(}) और (B={x:x\) 3 से विभाज्य है}), तो (|\(A'\cap B'\)|) कितना है? \(/ If (U={1,2,\ldots,36}), (A={x:x\) is divisible by \(2}) and (B={x:x\) is divisible by \(3}), what is (|(A'\cap B')|)\)?

Correct Answer: C. (12). Explanation: (A'\cap B'=\(A\cup B\)') होता है। \(|A\cup B|=18+12-6=24\), इसलिए पूरक में (36-24=12) अवयव हैं। / (A'\cap B'=\(A\cup B\)'). Since \(|A\cup B|=18+12-6=24\), the complement has (36-24=12) elements.

Which concept should I revise for this Mathematics MCQ?

(A'\cap B'=\(A\cup B\)'). Since \(|A\cup B|=18+12-6=24\), the complement has (36-24=12) elements.

What exam hint can help solve this Mathematics question?

(A'\cap B'=\(A\cup B\)') होता है। \(|A\cup B|=18+12-6=24\), इसलिए पूरक में (36-24=12) अवयव हैं।