\(यदि (U={1,2,\ldots,20}), (A={x:x\) 3 से विभाज्य है}), तो (A') में अवयवों की संख्या कितनी है?

\(If (U={1,2,\ldots,20}), (A={x:x\) is divisible by 3}), how many elements are in (A')?

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

There are (6) multiples of (3) up to (20), so (A') has (20-6=14) elements. For complement count, subtract from the total.

Step 2

Why this answer is correct

The correct answer is B. (14). There are (6) multiples of (3) up to (20), so (A') has (20-6=14) elements. For complement count, subtract from the total.

Step 3

Exam Tip

(20) तक (3) के (6) गुणज हैं, इसलिए (A') में (20-6=14) अवयव हैं। पूरक की संख्या के लिए कुल में से घटाएं।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,\ldots,20}), (A={x:x\) 3 से विभाज्य है}), तो (A') में अवयवों की संख्या कितनी है? \(/ If (U={1,2,\ldots,20}), (A={x:x\) is divisible by 3}), how many elements are in (A')?

Correct Answer: B. (14). Explanation: (20) तक (3) के (6) गुणज हैं, इसलिए (A') में (20-6=14) अवयव हैं। पूरक की संख्या के लिए कुल में से घटाएं। / There are (6) multiples of (3) up to (20), so (A') has (20-6=14) elements. For complement count, subtract from the total.

Which concept should I revise for this Mathematics MCQ?

There are (6) multiples of (3) up to (20), so (A') has (20-6=14) elements. For complement count, subtract from the total.

What exam hint can help solve this Mathematics question?

(20) तक (3) के (6) गुणज हैं, इसलिए (A') में (20-6=14) अवयव हैं। पूरक की संख्या के लिए कुल में से घटाएं।