\(यदि (U={1,2,3,\ldots,24}), (A={x:x\) 4 से विभाज्य है\(}) और (B={x:x\) 6 से विभाज्य है\(}) है, तो (A^c\cap B^c) में कितने तत्व होंगे\)?
\(If (U={1,2,3,\ldots,24}), (A={x:x\) is divisible by \(4}), and (B={x:x\) is divisible by \(6}), how many elements are in (A^c\cap B^c)\)?
Explanation opens after your attempt
Correct Answer
A. (16)
Concept
(A^c\cap B^c=\(A\cup B\)^c). Numbers divisible by (4) or (6) are (6+4-2=8), so the complement has (24-8=16) elements.
Why this answer is correct
The correct answer is A. (16). (A^c\cap B^c=\(A\cup B\)^c). Numbers divisible by (4) or (6) are (6+4-2=8), so the complement has (24-8=16) elements.
Exam Tip
(A^c\cap B^c=\(A\cup B\)^c) है। (4) या (6) से विभाज्य संख्याएं (6+4-2=8) हैं, इसलिए पूरक में (24-8=16) तत्व हैं।
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