\(यदि (U={1,2,3,\ldots,20}), (A={x:x\) अभाज्य है\(}) और (B={x:x\) विषम है\(}) है, तो (A^c\cap B) क्या होगा\)?

\(If (U={1,2,3,\ldots,20}), (A={x:x\) is prime\(}), and (B={x:x\) is odd\(}), what is (A^c\cap B)\)?

Explanation opens after your attempt
Correct Answer

A. ({1,9,15})

Step 1

Concept

\(A^c\cap B\) contains odd numbers that are not prime. (1), (9), and (15) satisfy this condition.

Step 2

Why this answer is correct

The correct answer is A. ({1,9,15}). \(A^c\cap B\) contains odd numbers that are not prime. (1), (9), and (15) satisfy this condition.

Step 3

Exam Tip

\(A^c\cap B\) में विषम लेकिन अभाज्य नहीं संख्याएं आएंगी। (1), (9) और (15) इस शर्त को पूरा करते हैं।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (U={1,2,3,\ldots,20}), (A={x:x\) अभाज्य है\(}) और (B={x:x\) विषम है}) है, तो \(A^c\cap B\) क्या होगा? \(/ If (U={1,2,3,\ldots,20}), (A={x:x\) is prime\(}), and (B={x:x\) is odd\(}), what is (A^c\cap B)\)?

Correct Answer: A. ({1,9,15}). Explanation: \(A^c\cap B\) में विषम लेकिन अभाज्य नहीं संख्याएं आएंगी। (1), (9) और (15) इस शर्त को पूरा करते हैं। / \(A^c\cap B\) contains odd numbers that are not prime. (1), (9), and (15) satisfy this condition.

Which concept should I revise for this Mathematics MCQ?

\(A^c\cap B\) contains odd numbers that are not prime. (1), (9), and (15) satisfy this condition.

What exam hint can help solve this Mathematics question?

\(A^c\cap B\) में विषम लेकिन अभाज्य नहीं संख्याएं आएंगी। (1), (9) और (15) इस शर्त को पूरा करते हैं।