यदि असमानताओं \(3x+y\leq 21\), \(x+3y\leq 21\), \(x\geq 0\), \(y\geq 0\) का हल-क्षेत्र है, तो (x-y) का अधिकतम मान क्या है?
If the solution region is \(3x+y\leq 21\), \(x+3y\leq 21\), \(x\geq 0\), and \(y\geq 0\), what is the maximum value of (x-y)?
Explanation opens after your attempt
Correct Answer
C. (7)
Concept
At the corner ((7,0)), (x-y=7), which is the largest value. For a linear expression, check the corner points.
Why this answer is correct
The correct answer is C. (7). At the corner ((7,0)), (x-y=7), which is the largest value. For a linear expression, check the corner points.
Exam Tip
कोनों में ((7,0)) पर (x-y=7) मिलता है जो सबसे बड़ा है। रैखिक व्यंजक का अधिकतम कोनों पर जांचें।
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