यदि वास्तविक फलन (f(x)=\frac{\sqrt{x-2}}{x-2-9}) दिया है, तो उसका प्रांत क्या है?
If the real function (f(x)=\frac{\sqrt{x-2}}{x-2-9}) is given, what is its domain?
Explanation opens after your attempt
Correct Answer
A. \([2,\infty\)-{3})
Concept
For the square root \(x\ge 2\), and for the denominator \(x\ne -3,3\) are required. But (-3) is already outside \(x\ge 2\), so only (3) is removed.
Why this answer is correct
The correct answer is A. \([2,\infty\)-{3}). For the square root \(x\ge 2\), and for the denominator \(x\ne -3,3\) are required. But (-3) is already outside \(x\ge 2\), so only (3) is removed.
Exam Tip
वर्गमूल के लिए \(x\ge 2\) और हर के लिए \(x\ne -3,3\) चाहिए। लेकिन (-3) पहले ही \(x\ge 2\) में नहीं है, इसलिए केवल (3) हटेगा।
Login to save your score, XP, coins and progress.