यदि पुनरावृत्ति allowed हो तो (4) अंकों से (3) स्थान भरने की संख्या कौन-सी होगी?
If repetition is allowed what is the number of ways to fill (3) positions using (4) digits?
Explanation opens after your attempt
Correct Answer
C. \(4^3\)
Concept
Each position again has (4) choices so the number of ways is \(4^3\). In exams do not decrease options when repetition is allowed.
Why this answer is correct
The correct answer is C. \(4^3\). Each position again has (4) choices so the number of ways is \(4^3\). In exams do not decrease options when repetition is allowed.
Exam Tip
हर स्थान पर (4) विकल्प फिर से मिलते हैं इसलिए \(4^3\) तरीके हैं। परीक्षा में repetition allowed हो तो options घटाएँ नहीं।
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