यदि केवल (A) में (12), केवल (B) में (15), केवल (C) में (18), केवल \(A\cap B\) में (9), केवल \(B\cap C\) में (7), केवल \(C\cap A\) में (6), और \(A\cap B\cap C\) में (4) हैं, तो (n(A\cap\(B\cup C\))) कितना है?
If only (A) has (12), only (B) has (15), only (C) has (18), only \(A\cap B\) has (9), only \(B\cap C\) has (7), only \(C\cap A\) has (6), and \(A\cap B\cap C\) has (4), then what is (n(A\cap\(B\cup C\)))?
Explanation opens after your attempt
A. (19)
Concept
(A\cap\(B\cup C\)) includes \(A\cap B\), \(A\cap C\), and the centre, so (9+6+4=19). The only (A) region is not included.
Why this answer is correct
The correct answer is A. (19). (A\cap\(B\cup C\)) includes \(A\cap B\), \(A\cap C\), and the centre, so (9+6+4=19). The only (A) region is not included.
Exam Tip
(A\cap\(B\cup C\)) में \(A\cap B\), \(A\cap C\) और केंद्र आते हैं, इसलिए (9+6+4=19) है। केवल (A) इसमें शामिल नहीं होगा।
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