यदि (n(U)=60), (n(A)=35), (n(B)=32) है, तो (n\(A\cap B\)) का न्यूनतम संभव मान कितना है?
If (n(U)=60), (n(A)=35), (n(B)=32), then what is the minimum possible value of (n\(A\cap B\))?
Explanation opens after your attempt
A. (7)
Concept
The minimum intersection is (35+32-60=7). If the sum exceeds (U), that much overlap is necessary.
Why this answer is correct
The correct answer is A. (7). The minimum intersection is (35+32-60=7). If the sum exceeds (U), that much overlap is necessary.
Exam Tip
न्यूनतम प्रतिच्छेद (35+32-60=7) होगा। यदि योग (U) से अधिक हो तो उतना अतिव्यापन अनिवार्य है।
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