यदि (n(U)=200), (n(A')=76), (n(B')=89) और (n\(A'\cap B'\)=31), तो (n(\(A\cap B\)')) क्या है?

If (n(U)=200), (n(A')=76), (n(B')=89), and (n\(A'\cap B'\)=31), what is (n(\(A\cap B\)'))?

Explanation opens after your attempt
Correct Answer

A. (134)

Step 1

Concept

By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).

Step 2

Why this answer is correct

The correct answer is A. (134). By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).

Step 3

Exam Tip

डी मॉर्गन से (\(A\cap B\)'=A'\cup B')। इसलिए (n\(A'\cup B'\)=76+89-31=134) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(U)=200), (n(A')=76), (n(B')=89) और (n\(A'\cap B'\)=31), तो (n(\(A\cap B\)')) क्या है? / If (n(U)=200), (n(A')=76), (n(B')=89), and (n\(A'\cap B'\)=31), what is (n(\(A\cap B\)'))?

Correct Answer: A. (134). Explanation: डी मॉर्गन से (\(A\cap B\)'=A'\cup B')। इसलिए (n\(A'\cup B'\)=76+89-31=134) है। / By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).

Which concept should I revise for this Mathematics MCQ?

By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).

What exam hint can help solve this Mathematics question?

डी मॉर्गन से (\(A\cap B\)'=A'\cup B')। इसलिए (n\(A'\cup B'\)=76+89-31=134) है।