यदि (n(U)=100), (n(A)=48), (n(B)=52) और (n\(A'\cap B'\)=18) है, तो (n\(A\cap B\)) क्या है?
If (n(U)=100), (n(A)=48), (n(B)=52), and (n\(A'\cap B'\)=18), what is (n\(A\cap B\))?
Explanation opens after your attempt
Correct Answer
A. (18)
Concept
\(A'\cap B'\) means outside both, so (n\(A\cup B\)=100-18=82). Now (48+52-n\(A\cap B\)=82), hence (18).
Why this answer is correct
The correct answer is A. (18). \(A'\cap B'\) means outside both, so (n\(A\cup B\)=100-18=82). Now (48+52-n\(A\cap B\)=82), hence (18).
Exam Tip
\(A'\cap B'\) का अर्थ दोनों से बाहर है, इसलिए (n\(A\cup B\)=100-18=82)। अब (48+52-n\(A\cap B\)=82), अतः (18)।
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