यदि \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\) है, तो (n) का मान क्या है?
If \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\), what is the value of (n)?
Explanation opens after your attempt
B. (9)
Concept
The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).
Why this answer is correct
The correct answer is B. (9). The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).
Exam Tip
समीकरण (1+n+\frac{n(n-1)}{2}=46) है। इससे (n=9) मिलता है।
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