यदि \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\) है, तो (n) का मान क्या है?

If \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).

Step 2

Why this answer is correct

The correct answer is B. (9). The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).

Step 3

Exam Tip

समीकरण (1+n+\frac{n(n-1)}{2}=46) है। इससे (n=9) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\) है, तो (n) का मान क्या है? / If \(^{n}C_{0}+^{n}C_{1}+^{n}C_{2}=46\), what is the value of (n)?

Correct Answer: B. (9). Explanation: समीकरण (1+n+\frac{n(n-1)}{2}=46) है। इससे (n=9) मिलता है। / The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).

Which concept should I revise for this Mathematics MCQ?

The equation is (1+n+\frac{n(n-1)}{2}=46). Solving gives (n=9).

What exam hint can help solve this Mathematics question?

समीकरण (1+n+\frac{n(n-1)}{2}=46) है। इससे (n=9) मिलता है।