यदि (n\(A\triangle B\)=64) और (n(A-B)=27) है, तो (n(B-A)) कितना होगा?

If (n\(A\triangle B\)=64) and (n(A-B)=27), what is (n(B-A))?

Explanation opens after your attempt
Correct Answer

A. (37)

Step 1

Concept

The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.

Step 2

Why this answer is correct

The correct answer is A. (37). The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.

Step 3

Exam Tip

सममित अंतर (A-B) और (B-A) का योग है, इसलिए (64-27=37)। साझा भाग इसमें नहीं आता।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\triangle B\)=64) और (n(A-B)=27) है, तो (n(B-A)) कितना होगा? / If (n\(A\triangle B\)=64) and (n(A-B)=27), what is (n(B-A))?

Correct Answer: A. (37). Explanation: सममित अंतर (A-B) और (B-A) का योग है, इसलिए (64-27=37)। साझा भाग इसमें नहीं आता। / The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.

Which concept should I revise for this Mathematics MCQ?

The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.

What exam hint can help solve this Mathematics question?

सममित अंतर (A-B) और (B-A) का योग है, इसलिए (64-27=37)। साझा भाग इसमें नहीं आता।