यदि (n\(A\triangle B\)=64) और (n(A-B)=27) है, तो (n(B-A)) कितना होगा?
If (n\(A\triangle B\)=64) and (n(A-B)=27), what is (n(B-A))?
Explanation opens after your attempt
A. (37)
Concept
The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.
Why this answer is correct
The correct answer is A. (37). The symmetric difference is the sum of (A-B) and (B-A), so (64-27=37). The common part is not included.
Exam Tip
सममित अंतर (A-B) और (B-A) का योग है, इसलिए (64-27=37)। साझा भाग इसमें नहीं आता।
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