यदि (n\(A\triangle B\)=112) और (n\(A\cap B\)=39) है, तो (n\(A\cup B\)) कितना होगा?

If (n\(A\triangle B\)=112) and (n\(A\cap B\)=39), what is (n\(A\cup B\))?

Explanation opens after your attempt
Correct Answer

C. (151)

Step 1

Concept

The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.

Step 2

Why this answer is correct

The correct answer is C. (151). The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.

Step 3

Exam Tip

संघ में सममित अंतर और साझा भाग दोनों आते हैं, इसलिए (112+39=151)। \(A\triangle B\) में साझा भाग शामिल नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\triangle B\)=112) और (n\(A\cap B\)=39) है, तो (n\(A\cup B\)) कितना होगा? / If (n\(A\triangle B\)=112) and (n\(A\cap B\)=39), what is (n\(A\cup B\))?

Correct Answer: C. (151). Explanation: संघ में सममित अंतर और साझा भाग दोनों आते हैं, इसलिए (112+39=151)। \(A\triangle B\) में साझा भाग शामिल नहीं होता। / The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.

Which concept should I revise for this Mathematics MCQ?

The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.

What exam hint can help solve this Mathematics question?

संघ में सममित अंतर और साझा भाग दोनों आते हैं, इसलिए (112+39=151)। \(A\triangle B\) में साझा भाग शामिल नहीं होता।