यदि (n\(A\triangle B\)=112) और (n\(A\cap B\)=39) है, तो (n\(A\cup B\)) कितना होगा?
If (n\(A\triangle B\)=112) and (n\(A\cap B\)=39), what is (n\(A\cup B\))?
Explanation opens after your attempt
C. (151)
Concept
The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.
Why this answer is correct
The correct answer is C. (151). The union contains both the symmetric difference and the common part, so (112+39=151). \(A\triangle B\) does not include the common part.
Exam Tip
संघ में सममित अंतर और साझा भाग दोनों आते हैं, इसलिए (112+39=151)। \(A\triangle B\) में साझा भाग शामिल नहीं होता।
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