यदि (n\(A\times B\)=n\(B\times C\)=30), (n(B)=5), और (A,B,C) अशून्य सीमित समुच्चय हैं, तो (n\(A\times C\)) कितना होगा?

If (n\(A\times B\)=n\(B\times C\)=30), (n(B)=5), and (A,B,C) are non-empty finite sets, what is (n\(A\times C\))?

Explanation opens after your attempt
Correct Answer

C. (36)

Step 1

Concept

(n(A)=30/5=6) and (n(C)=30/5=6). Therefore (n\(A\times C\)=6\cdot6=36).

Step 2

Why this answer is correct

The correct answer is C. (36). (n(A)=30/5=6) and (n(C)=30/5=6). Therefore (n\(A\times C\)=6\cdot6=36).

Step 3

Exam Tip

(n(A)=30/5=6) और (n(C)=30/5=6)। इसलिए (n\(A\times C\)=6\cdot6=36)।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\times B\)=n\(B\times C\)=30), (n(B)=5), और (A,B,C) अशून्य सीमित समुच्चय हैं, तो (n\(A\times C\)) कितना होगा? / If (n\(A\times B\)=n\(B\times C\)=30), (n(B)=5), and (A,B,C) are non-empty finite sets, what is (n\(A\times C\))?

Correct Answer: C. (36). Explanation: (n(A)=30/5=6) और (n(C)=30/5=6)। इसलिए (n\(A\times C\)=6\cdot6=36)। / (n(A)=30/5=6) and (n(C)=30/5=6). Therefore (n\(A\times C\)=6\cdot6=36).

Which concept should I revise for this Mathematics MCQ?

(n(A)=30/5=6) and (n(C)=30/5=6). Therefore (n\(A\times C\)=6\cdot6=36).

What exam hint can help solve this Mathematics question?

(n(A)=30/5=6) और (n(C)=30/5=6)। इसलिए (n\(A\times C\)=6\cdot6=36)।