यदि (n\(A\setminus B\)=12), (n\(B\setminus A\)=9) और (n\(A\cap B\)=6) है, तो (n\(A\cup B\)) कितना है?
If (n\(A\setminus B\)=12), (n\(B\setminus A\)=9), and (n\(A\cap B\)=6), then what is (n\(A\cup B\))?
Explanation opens after your attempt
A. (27)
Concept
The union is the sum of these three disjoint parts. Therefore (n\(A\cup B\)=12+9+6=27).
Why this answer is correct
The correct answer is A. (27). The union is the sum of these three disjoint parts. Therefore (n\(A\cup B\)=12+9+6=27).
Exam Tip
संघ इन तीन असंबद्ध भागों का योग है। इसलिए (n\(A\cup B\)=12+9+6=27)।
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